WebDec 22, 2009 · get url with parameters. Reply. Rachael. Permalink to comment # January 23, 2014. Thanks – what I needed. ... array would get the end if you don’t want to have to specify the index and you know it is the everything after the last ‘/’ that you want to get. ... But I wanna know how to get the url part after a “=” equal icon ! WebJul 11, 2024 · If you want to get the last part of a URL without the query string, just use the property name window.location.pathname instead of window.location.href. const slug = window.location.pathname.substring ( window.location.pathname.lastIndexOf ("/") + 1 ); Get URL without query parameters in general
Get last part of URL after last slash - social.msdn.microsoft.com
WebMar 25, 2024 · This snippet shows how to get the last part of an URL with PHP. It's a kind of a relic of the past! Indeed, this basename () function can typically return the "script" … WebJun 10, 2015 · if ($request_uri ~* "([^/]*$)" ) { set $last_path_component $1; } You can then use the $last_path_component var anywhere you wish. Note this regex will return … is it a sin to snitch
Get last part of URL after last slash - social.msdn.microsoft.com
WebJun 14, 2024 · How to get last part of the url using jQuery? jQuery – get last part of URL $(function () { siteCode = getLastPartOfUrl(‘www.example.com/folder/code/12345/’); var getLastPartOfUrl =function($url) { var url = $url; var urlsplit = url. split(“/”); var lastpart = urlsplit[urlsplit. length-1]; if(lastpart===”) How do you find the last part of a URL? WebAug 22, 2024 · How to get the last string in JavaScript? Now you have the last.htm in the path string. start = Required. The position where to start the extraction. First character is at index 0`. end = Optional. The position (up to, but not including) where to end the extraction. If omitted, it extracts the rest of the string. Web@Component( {templateUrl:'template.html'}) class MyComponent { constructor(router: Router) { const tree: UrlTree = router.parseUrl('/team;id=33'); const g: UrlSegmentGroup = tree.root.children[PRIMARY_OUTLET]; const s: UrlSegment[] = g.segments; s[0].path; // returns 'team' s[0].parameters; // returns {id: 33} } } is it a sin to sue